18x^2+24x-792=0

Solution for 18x^2+24x-792=0 equation:

18x^2+24x-792=0

a = 18; b = 24; c = -792;
Δ = b2-4ac
Δ = 242-4·18·(-792)
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-240}{2*18}=\frac{-264}{36}
=-7+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+240}{2*18}=\frac{216}{36}
=6
$